Heat transfer I
This problem demonstrates using LS-DYNA to solve a 2-dimensional steady state heat transfer problem with temperature boundary conditions. Shell formulation 12 for plane geometry is used. Download is available in the download section of this document.
Keywords
Keywords
The used Keywords in alphabetical order.
*BOUNDARY_TEMPERATURE_NODE *CONTROL_SOLUTION *CONTROL_TERMINATION *CONTROL_THERMAL_SOLVER *DATABASE_BINARY_D3PLOT *DATABASE_TPRINT *ELEMENT_SHELL *END *KEYWORD *MAT_THERMAL_ISOTROPIC *NODE *PART *SECTION_SHELL *TITLE
Reduced Input
Reduced Input
*Node and *Element Cards are removed.
$ 2-Dimensional Heat Transfer
$
$ 2--------4--------6 boundary conditions
$ | | | T=0. at nodes 1,2
$ | | | T=2. st nodes 5,6
$ | | |
$ 1--------3--------5 analytical answer T=1. at nodes 3,4
$
*KEYWORD
$
$=============================CONTROL DEFINITIONS ==============================
$
*TITLE
steady state conduction in a slab
*CONTROL_SOLUTION
1
*CONTROL_THERMAL_SOLVER
0 0 1
*CONTROL_TERMINATION
1.
*DATABASE_TPRINT
1.
*DATABASE_BINARY_D3PLOT
1.
$
$============================== PART DEFINITIONS ===============================
$
*PART
$ PID SECID MID TMID
slab
1 1 1
$
$============================= SECTION PROPERTIES ==============================
$
*SECTION_SHELL
$ SECID ELFORM
1 12
0.001 0.001 0.001 0.001 0.
$
$======================== THERMAL MATERIAL PROPERTIES ==========================
$
*MAT_THERMAL_ISOTROPIC
1 1.
1. 1.
$
$============================= NODE DEFINTIONS =================================
$
*NODE
1 0. 0.
2 0. 1.
3 1. 0.
4 1. 1.
5 2. 0.
6 2. 1.
$
$============================ ELEMENT DEFINITIONS ==============================
$
*ELEMENT_SHELL
1 1 1 3 4 2
2 1 3 5 6 4
$
$======================== THERMAL BOUNDARY CONDITIONS ==========================
$
*BOUNDARY_TEMPERATURE_NODE
1 0 0.
2 0 0.
5 0 2.
6 0 2.
*END
Figures
Figures
Animated Result
Animated Result
